A body falling for 2 seconds covers a distance S equal to t…

Physics Motion in a Straight Line Motion Under Gravity Single Correct MCQ

Published on: September 12, 2026

A body falling for 2 seconds covers a distance S equal to that covered in next second. Taking \(g = 10 \, m/s^{2}, \, S \equiv\)

30 m

10 m

60 m

20 m

Text Solution

Verified by Experts

The correct answer is:

If u is the initial velocity then distance covered by it in 2 sec

\(S = ut + \frac{1}{2}at^{2} = u \times 2 + \frac{1}{2} \times 10 \times 4 = 2u + 20\) …(i)

Now distance covered by it in 3 rd sec

\(S_{3^{rd}} = u + \frac{g}{2} (2 \times 3 - 1) 10 = u + 25\) …(ii)

From(i) and (ii), \(2u + 20 = u + 25 \Rightarrow u = 5\)

\(S = 2 \times 5 + 20 = 30 \, m\)

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